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2(3x-2)-5=2(2x-4)
We move all terms to the left:
2(3x-2)-5-(2(2x-4))=0
We multiply parentheses
6x-(2(2x-4))-4-5=0
We calculate terms in parentheses: -(2(2x-4)), so:We add all the numbers together, and all the variables
2(2x-4)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
6x-(4x-8)-9=0
We get rid of parentheses
6x-4x+8-9=0
We add all the numbers together, and all the variables
2x-1=0
We move all terms containing x to the left, all other terms to the right
2x=1
x=1/2
x=1/2
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