0.4(10x-40)-2x=-3(2x-2)+6x

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Solution for 0.4(10x-40)-2x=-3(2x-2)+6x equation: 



0.4(10x-40)-2x=-3(2x-2)+6x

We move all terms to the left:

0.4(10x-40)-2x-(-3(2x-2)+6x)=0

We add all the numbers together, and all the variables

-2x+0.4(10x-40)-(-3(2x-2)+6x)=0

We multiply parentheses

-2x+4x-(-3(2x-2)+6x)-16=0



We calculate terms in parentheses: -(-3(2x-2)+6x), so:

-3(2x-2)+6x

We add all the numbers together, and all the variables

6x-3(2x-2)

We multiply parentheses

6x-6x+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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