(3x-7)=(7x-17)+(x+20)

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Solution for (3x-7)=(7x-17)+(x+20) equation: 



(3x-7)=(7x-17)+(x+20)

We move all terms to the left:

(3x-7)-((7x-17)+(x+20))=0

We get rid of parentheses

3x-((7x-17)+(x+20))-7=0



We calculate terms in parentheses: -((7x-17)+(x+20)), so:

(7x-17)+(x+20)

We get rid of parentheses

7x+x-17+20

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

3x-8x-3-7=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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