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0.3x+3/2x=x+7
We move all terms to the left:
0.3x+3/2x-(x+7)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
0.3x+3/2x-x-7=0
We multiply all the terms by the denominator
(0.3x)*2x-x*2x-7*2x+3=0
We add all the numbers together, and all the variables
(+0.3x)*2x-x*2x-7*2x+3=0
We multiply parentheses
0x^2-x*2x-7*2x+3=0
Wy multiply elements
0x^2-2x^2-14x+3=0
We add all the numbers together, and all the variables
-1x^2-14x+3=0
a = -1; b = -14; c = +3;
Δ = b2-4ac
Δ = -142-4·(-1)·3
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-4\sqrt{13}}{2*-1}=\frac{14-4\sqrt{13}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+4\sqrt{13}}{2*-1}=\frac{14+4\sqrt{13}}{-2} $
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