3(2-3x)=3(2x+3)

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Solution for 3(2-3x)=3(2x+3) equation: 



3(2-3x)=3(2x+3)

We move all terms to the left:

3(2-3x)-(3(2x+3))=0

We add all the numbers together, and all the variables

3(-3x+2)-(3(2x+3))=0

We multiply parentheses

-9x-(3(2x+3))+6=0



We calculate terms in parentheses: -(3(2x+3)), so:

3(2x+3)

We multiply parentheses

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

-9x-6x-9+6=0

We add all the numbers together, and all the variables

-15x-3=0

We move all terms containing x to the left, all other terms to the right

-15x=3

x=3/-15

x=-1/5

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