0.25x2+1.75x+1.5=0

Solution for 0.25x2+1.75x+1.5=0 equation:

0.25x^2+1.75x+1.5=0

a = 0.25; b = 1.75; c = +1.5;
Δ = b2-4ac
Δ = 1.752-4·0.25·1.5
Δ = 1.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.75)-\sqrt{1.5625}}{2*0.25}=\frac{-1.75-\sqrt{1.5625}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.75)+\sqrt{1.5625}}{2*0.25}=\frac{-1.75+\sqrt{1.5625}}{0.5}
$