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x+2(x-7)=3(x-5)+1
We move all terms to the left:
x+2(x-7)-(3(x-5)+1)=0
We multiply parentheses
x+2x-(3(x-5)+1)-14=0
We calculate terms in parentheses: -(3(x-5)+1), so:We add all the numbers together, and all the variables
3(x-5)+1
We multiply parentheses
3x-15+1
We add all the numbers together, and all the variables
3x-14
Back to the equation:
-(3x-14)
3x-(3x-14)-14=0
We get rid of parentheses
3x-3x+14-14=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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