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0.25x+1.5=2(1/2x-3)
We move all terms to the left:
0.25x+1.5-(2(1/2x-3))=0
Domain of the equation: 2x-3))!=0We multiply all the terms by the denominator
x∈R
(0.25x)*2x+(1.5)*2x-3))-(2(1-3))=0
We add all the numbers together, and all the variables
(+0.25x)*2x+(1.5)*2x-3))-(2(-2))=0
We add all the numbers together, and all the variables
(+0.25x)*2x+(1.5)*2x=0
We multiply parentheses
0x^2+3x=0
We add all the numbers together, and all the variables
x^2+3x=0
a = 1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·1·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*1}=\frac{-6}{2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*1}=\frac{0}{2} =0 $
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