8*(3*x+2)+(2*(3*x+4))/1-(2*x)=28

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Solution for 8*(3*x+2)+(2*(3*x+4))/1-(2*x)=28 equation: 



8(3x+2)+(2(3x+4))/1-(2x)=28

We move all terms to the left:

8(3x+2)+(2(3x+4))/1-(2x)-(28)=0

We add all the numbers together, and all the variables

-2x+8(3x+2)+(2(3x+4))/1-28=0

We multiply parentheses

-2x+24x+(2(3x+4))/1+16-28=0

We multiply all the terms by the denominator


-2x*1+24x*1+(2(3x+4))+16*1-28*1=0



We calculate terms in parentheses: +(2(3x+4)), so:

2(3x+4)

We multiply parentheses

6x+8

Back to the equation:

+(6x+8)



We add all the numbers together, and all the variables

-2x*1+24x*1+(6x+8)-12=0

Wy multiply elements

-2x+24x+(6x+8)-12=0

We get rid of parentheses

-2x+24x+6x+8-12=0

We add all the numbers together, and all the variables

28x-4=0

We move all terms containing x to the left, all other terms to the right

28x=4

x=4/28

x=1/7

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