0.23x+0.2(x-4)=0.01(3x-7)

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Solution for 0.23x+0.2(x-4)=0.01(3x-7) equation: 



0.23x+0.2(x-4)=0.01(3x-7)

We move all terms to the left:

0.23x+0.2(x-4)-(0.01(3x-7))=0

We multiply parentheses

0.23x+0.2x-(0.01(3x-7))-0.8=0



We calculate terms in parentheses: -(0.01(3x-7)), so:

0.01(3x-7)

We multiply parentheses

0.03x-0.07

Back to the equation:

-(0.03x-0.07)



We add all the numbers together, and all the variables

0.43x-(0.03x-0.07)-0.8=0

We get rid of parentheses

0.43x-0.03x+0.07-0.8=0

We add all the numbers together, and all the variables

0.4x-0.73=0

We move all terms containing x to the left, all other terms to the right

0.4x=0.73

x=0.73/0.4

x=1+0.33/0.4

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