x2=25121

Solution for x2=25121 equation:

x2=25121

We move all terms to the left:

x2-(25121)=0

We add all the numbers together, and all the variables

x^2-25121=0

a = 1; b = 0; c = -25121;
Δ = b2-4ac
Δ = 02-4·1·(-25121)
Δ = 100484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100484}=\sqrt{4*25121}=\sqrt{4}*\sqrt{25121}=2\sqrt{25121}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{25121}}{2*1}=\frac{0-2\sqrt{25121}}{2}
=-\frac{2\sqrt{25121}}{2}
=-\sqrt{25121}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{25121}}{2*1}=\frac{0+2\sqrt{25121}}{2}
=\frac{2\sqrt{25121}}{2}
=\sqrt{25121}
$