0.22x+0.2(x-4)=0.01(2x-3)

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Solution for 0.22x+0.2(x-4)=0.01(2x-3) equation: 



0.22x+0.2(x-4)=0.01(2x-3)

We move all terms to the left:

0.22x+0.2(x-4)-(0.01(2x-3))=0

We multiply parentheses

0.22x+0.2x-(0.01(2x-3))-0.8=0



We calculate terms in parentheses: -(0.01(2x-3)), so:

0.01(2x-3)

We multiply parentheses

0.02x-0.03

Back to the equation:

-(0.02x-0.03)



We add all the numbers together, and all the variables

0.42x-(0.02x-0.03)-0.8=0

We get rid of parentheses

0.42x-0.02x+0.03-0.8=0

We add all the numbers together, and all the variables

0.4x-0.77=0

We move all terms containing x to the left, all other terms to the right

0.4x=0.77

x=0.77/0.4

x=1+0.37/0.4

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