0.2(x-20)=40-x

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Solution for 0.2(x-20)=40-x equation: 



0.2(x-20)=40-x

We move all terms to the left:

0.2(x-20)-(40-x)=0

We add all the numbers together, and all the variables

0.2(x-20)-(-1x+40)=0

We multiply parentheses

0.2x-(-1x+40)-4=0

We get rid of parentheses

0.2x+1x-40-4=0

We add all the numbers together, and all the variables

1.2x-44=0

We move all terms containing x to the left, all other terms to the right

1.2x=44

x=44/1.2

x=36+0.8/1.2

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