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(8x+11)(5x-6)=0
We multiply parentheses ..
(+40x^2-48x+55x-66)=0
We get rid of parentheses
40x^2-48x+55x-66=0
We add all the numbers together, and all the variables
40x^2+7x-66=0
a = 40; b = 7; c = -66;
Δ = b2-4ac
Δ = 72-4·40·(-66)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10609}=103$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-103}{2*40}=\frac{-110}{80} =-1+3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+103}{2*40}=\frac{96}{80} =1+1/5 $
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