0.2(x+50)-6=2/5(3x=20)

Solution for 0.2(x+50)-6=2/5(3x=20) equation:

0.2(x+50)-6=2/5(3x=20)

We move all terms to the left:

0.2(x+50)-6-(2/5(3x)=0


Domain of the equation: 53x-6!=0

We move all terms containing x to the left, all other terms to the right

53x!=6

x!=6/53

x!=6/53

x∈R


We multiply parentheses

0.2x-(2/53x-6+10=0

We multiply all the terms by the denominator


(0.2x)*53x-6+10-(2=0

We add all the numbers together, and all the variables

(+0.2x)*53x-6+10-(2=0

We add all the numbers together, and all the variables

(+0.2x)*53x=0

We multiply parentheses

0x^2=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$