0.2(1d-6)=0.3d+5-3+0.1d

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Solution for 0.2(1d-6)=0.3d+5-3+0.1d equation: 



0.2(1d-6)=0.3d+5-3+0.1d

We move all terms to the left:

0.2(1d-6)-(0.3d+5-3+0.1d)=0

We add all the numbers together, and all the variables

0.2(d-6)-(0.4d+2)=0

We multiply parentheses

0.2d-(0.4d+2)-1.2=0

We get rid of parentheses

0.2d-0.4d-2-1.2=0

We add all the numbers together, and all the variables

-0.2d-3.2=0

We move all terms containing d to the left, all other terms to the right

-0.2d=3.2

d=3.2/-0.2

d=-16

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