-8-8r(-2-8r)=2-7(-6-6r)

Solution for -8-8r(-2-8r)=2-7(-6-6r) equation:

-8-8r(-2-8r)=2-7(-6-6r)

We move all terms to the left:

-8-8r(-2-8r)-(2-7(-6-6r))=0

We add all the numbers together, and all the variables

-8r(-8r-2)-(2-7(-6r-6))-8=0

We multiply parentheses

64r^2+16r-(2-7(-6r-6))-8=0


We calculate terms in parentheses: -(2-7(-6r-6)), so:

2-7(-6r-6)

determiningTheFunctionDomain
-7(-6r-6)+2

We multiply parentheses

42r+42+2

We add all the numbers together, and all the variables

42r+44

Back to the equation:

-(42r+44)


We get rid of parentheses

64r^2+16r-42r-44-8=0

We add all the numbers together, and all the variables

64r^2-26r-52=0

a = 64; b = -26; c = -52;
Δ = b2-4ac
Δ = -262-4·64·(-52)
Δ = 13988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13988}=\sqrt{4*3497}=\sqrt{4}*\sqrt{3497}=2\sqrt{3497}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{3497}}{2*64}=\frac{26-2\sqrt{3497}}{128}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{3497}}{2*64}=\frac{26+2\sqrt{3497}}{128}
$