0.2(10x-20)=4x-6x+2

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Solution for 0.2(10x-20)=4x-6x+2 equation: 



0.2(10x-20)=4x-6x+2

We move all terms to the left:

0.2(10x-20)-(4x-6x+2)=0

We add all the numbers together, and all the variables

0.2(10x-20)-(-2x+2)=0

We multiply parentheses

2x-(-2x+2)-4=0

We get rid of parentheses

2x+2x-2-4=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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