0.1x=0.2(x2)

Solution for 0.1x=0.2(x2) equation:

0.1x=0.2(x2)

We move all terms to the left:

0.1x-(0.2(x2))=0

We add all the numbers together, and all the variables

-(+0.2x^2)+0.1x=0

We get rid of parentheses

-0.2x^2+0.1x=0

a = -0.2; b = 0.1; c = 0;
Δ = b2-4ac
Δ = 0.12-4·(-0.2)·0
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1)-\sqrt{0.01}}{2*-0.2}=\frac{-0.1-\sqrt{0.01}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1)+\sqrt{0.01}}{2*-0.2}=\frac{-0.1+\sqrt{0.01}}{-0.4}
$