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1/3(9x+3x)=3x+1
We move all terms to the left:
1/3(9x+3x)-(3x+1)=0
Domain of the equation: 3(9x+3x)!=0We add all the numbers together, and all the variables
x∈R
1/3(+12x)-(3x+1)=0
We get rid of parentheses
1/3(+12x)-3x-1=0
We multiply all the terms by the denominator
-3x*3(+12x)-1*3(+12x)+1=0
Wy multiply elements
-9x^2(+-3x(++1=0
We use the square of the difference formula
-9x^2(-3x(+1=0
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