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0.16x^2-20x+260=0
a = 0.16; b = -20; c = +260;
Δ = b2-4ac
Δ = -202-4·0.16·260
Δ = 233.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-\sqrt{233.6}}{2*0.16}=\frac{20-\sqrt{233.6}}{0.32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+\sqrt{233.6}}{2*0.16}=\frac{20+\sqrt{233.6}}{0.32} $
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