(10x+8)+(5x-4)=(12x+16)

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Solution for (10x+8)+(5x-4)=(12x+16) equation: 



(10x+8)+(5x-4)=(12x+16)

We move all terms to the left:

(10x+8)+(5x-4)-((12x+16))=0

We get rid of parentheses

10x+5x-((12x+16))+8-4=0



We calculate terms in parentheses: -((12x+16)), so:

(12x+16)

We get rid of parentheses

12x+16

Back to the equation:

-(12x+16)



We add all the numbers together, and all the variables

15x-(12x+16)+4=0

We get rid of parentheses

15x-12x-16+4=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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