0.15b(b-0.2)=2-0.5(1-b)

Solution for 0.15b(b-0.2)=2-0.5(1-b) equation:

0.15b(b-0.2)=2-0.5(1-b)

We move all terms to the left:

0.15b(b-0.2)-(2-0.5(1-b))=0

We add all the numbers together, and all the variables

0.15b(b-0.2)-(2-0.5(-1b+1))=0

We multiply parentheses

0b^2-0b-(2-0.5(-1b+1))=0


We calculate terms in parentheses: -(2-0.5(-1b+1)), so:

2-0.5(-1b+1)

determiningTheFunctionDomain
-0.5(-1b+1)+2

We multiply parentheses

0.5b-0.5+2

We add all the numbers together, and all the variables

0.5b+1.5

Back to the equation:

-(0.5b+1.5)


We add all the numbers together, and all the variables

b^2-1b-(0.5b+1.5)=0

We get rid of parentheses

b^2-1b-0.5b-1.5=0

We add all the numbers together, and all the variables

b^2-1.5b-1.5=0

a = 1; b = -1.5; c = -1.5;
Δ = b2-4ac
Δ = -1.52-4·1·(-1.5)
Δ = 8.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{8.25}}{2*1}=\frac{1.5-\sqrt{8.25}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{8.25}}{2*1}=\frac{1.5+\sqrt{8.25}}{2}
$