0.12y+0.02(y+2000)=1300

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Solution for 0.12y+0.02(y+2000)=1300 equation: 



0.12y+0.02(y+2000)=1300

We move all terms to the left:

0.12y+0.02(y+2000)-(1300)=0

We multiply parentheses

0.12y+0.02y+40-1300=0

We add all the numbers together, and all the variables

0.14y-1260=0

We move all terms containing y to the left, all other terms to the right

0.14y=1260

y=1260/0.14

y=9000+-2.2737367544323E-13/0.14

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