(3x-2)+(3x+18)+2x+(4x-4)=360

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Solution for (3x-2)+(3x+18)+2x+(4x-4)=360 equation:



(3x-2)+(3x+18)+2x+(4x-4)=360
We move all terms to the left:
(3x-2)+(3x+18)+2x+(4x-4)-(360)=0
We add all the numbers together, and all the variables
2x+(3x-2)+(3x+18)+(4x-4)-360=0
We get rid of parentheses
2x+3x+3x+4x-2+18-4-360=0
We add all the numbers together, and all the variables
12x-348=0
We move all terms containing x to the left, all other terms to the right
12x=348
x=348/12
x=29

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