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5(2y-3)=3(y+3)
We move all terms to the left:
5(2y-3)-(3(y+3))=0
We multiply parentheses
10y-(3(y+3))-15=0
We calculate terms in parentheses: -(3(y+3)), so:We get rid of parentheses
3(y+3)
We multiply parentheses
3y+9
Back to the equation:
-(3y+9)
10y-3y-9-15=0
We add all the numbers together, and all the variables
7y-24=0
We move all terms containing y to the left, all other terms to the right
7y=24
y=24/7
y=3+3/7
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