0.12x+0.6(x-3)=0.01(4x-3)

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Solution for 0.12x+0.6(x-3)=0.01(4x-3) equation: 



0.12x+0.6(x-3)=0.01(4x-3)

We move all terms to the left:

0.12x+0.6(x-3)-(0.01(4x-3))=0

We multiply parentheses

0.12x+0.6x-(0.01(4x-3))-1.8=0



We calculate terms in parentheses: -(0.01(4x-3)), so:

0.01(4x-3)

We multiply parentheses

0.04x-0.03

Back to the equation:

-(0.04x-0.03)



We add all the numbers together, and all the variables

0.72x-(0.04x-0.03)-1.8=0

We get rid of parentheses

0.72x-0.04x+0.03-1.8=0

We add all the numbers together, and all the variables

0.68x-1.77=0

We move all terms containing x to the left, all other terms to the right

0.68x=1.77

x=1.77/0.68

x=2+0.41/0.68

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