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4(x+1)-3=2x+2(1+x)
We move all terms to the left:
4(x+1)-3-(2x+2(1+x))=0
We add all the numbers together, and all the variables
4(x+1)-(2x+2(x+1))-3=0
We multiply parentheses
4x-(2x+2(x+1))+4-3=0
We calculate terms in parentheses: -(2x+2(x+1)), so:We add all the numbers together, and all the variables
2x+2(x+1)
We multiply parentheses
2x+2x+2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
4x-(4x+2)+1=0
We get rid of parentheses
4x-4x-2+1=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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