0.12(y-4)+0.06y=0.10y-0.2

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Solution for 0.12(y-4)+0.06y=0.10y-0.2 equation: 



0.12(y-4)+0.06y=0.10y-0.2

We move all terms to the left:

0.12(y-4)+0.06y-(0.10y-0.2)=0

We add all the numbers together, and all the variables

0.06y+0.12(y-4)-(0.10y-0.2)=0

We multiply parentheses

0.06y+0.12y-(0.10y-0.2)-0.48=0

We get rid of parentheses

0.06y+0.12y-0.10y+0.2-0.48=0

We add all the numbers together, and all the variables

0.08y-0.28=0

We move all terms containing y to the left, all other terms to the right

0.08y=0.28

y=0.28/0.08

y=3+0.04/0.08

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