0.12(y-2)+0.06y=0.20y-0.01(10)

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Solution for 0.12(y-2)+0.06y=0.20y-0.01(10) equation: 



0.12(y-2)+0.06y=0.20y-0.01(10)

We move all terms to the left:

0.12(y-2)+0.06y-(0.20y-0.01(10))=0

We add all the numbers together, and all the variables

0.12(y-2)+0.06y-(0.20y-0.011)=0

We add all the numbers together, and all the variables

0.06y+0.12(y-2)-(0.20y-0.011)=0

We multiply parentheses

0.06y+0.12y-(0.20y-0.011)-0.24=0

We get rid of parentheses

0.06y+0.12y-0.20y+0.011-0.24=0

We add all the numbers together, and all the variables

-0.02y-0.229=0

We move all terms containing y to the left, all other terms to the right

-0.02y=0.229

y=0.229/-0.02

y=-11+0.009/0.02

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