4(3x-5)=7(4x+9)+13

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Solution for 4(3x-5)=7(4x+9)+13 equation: 



4(3x-5)=7(4x+9)+13

We move all terms to the left:

4(3x-5)-(7(4x+9)+13)=0

We multiply parentheses

12x-(7(4x+9)+13)-20=0



We calculate terms in parentheses: -(7(4x+9)+13), so:

7(4x+9)+13

We multiply parentheses

28x+63+13

We add all the numbers together, and all the variables

28x+76

Back to the equation:

-(28x+76)



We get rid of parentheses

12x-28x-76-20=0

We add all the numbers together, and all the variables

-16x-96=0

We move all terms containing x to the left, all other terms to the right

-16x=96

x=96/-16

x=-6

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