0.10x+(x+3)0.25+(2x)0.5+(4x)0.1=7.61

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Solution for 0.10x+(x+3)0.25+(2x)0.5+(4x)0.1=7.61 equation: 



0.10x+(x+3)0.25+(2x)0.5+(4x)0.1=7.61

We move all terms to the left:

0.10x+(x+3)0.25+(2x)0.5+(4x)0.1-(7.61)=0

We add all the numbers together, and all the variables

0.10x+(x+3)0.25+2x0.5+4x0.1-7.61=0

We multiply parentheses

0.10x+0.25x+2x0.5+4x0.1+0.75-7.61=0

We add all the numbers together, and all the variables

0.35x+2x0.5+4x0.1-6.86=0

We move all terms containing x to the left, all other terms to the right

0.35x+2x0.5+4x0.1=6.86

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