(4-s)/2=(s+1)/3

Solution for (4-s)/2=(s+1)/3 equation:

(4-s)/2=(s+1)/3

We move all terms to the left:

(4-s)/2-((s+1)/3)=0

We add all the numbers together, and all the variables

(-1s+4)/2-((s+1)/3)=0

We calculate fractions


(-s)/()+(-((s+1)*2)/()=0


We calculate terms in parentheses: +(-((s+1)*2)/(), so:

-((s+1)*2)/(

We multiply all the terms by the denominator


-((s+1)*2)


We calculate terms in parentheses: -((s+1)*2), so:

(s+1)*2

We multiply parentheses

2s+2

Back to the equation:

-(2s+2)


We get rid of parentheses

-2s-2

Back to the equation:

+(-2s-2)


We add all the numbers together, and all the variables

(-1s)/()+(-2s-2)=0

We get rid of parentheses

(-1s)/()-2s-2=0

We multiply all the terms by the denominator


(-1s)-2s*()-2*()=0

We add all the numbers together, and all the variables

(-1s)-2s*()=0

We get rid of parentheses

-1s-2s*()=0