0.02(y-6)+0.12y=0.10y-0.05(10)

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Solution for 0.02(y-6)+0.12y=0.10y-0.05(10) equation: 



0.02(y-6)+0.12y=0.10y-0.05(10)

We move all terms to the left:

0.02(y-6)+0.12y-(0.10y-0.05(10))=0

We add all the numbers together, and all the variables

0.02(y-6)+0.12y-(0.10y-0.051)=0

We add all the numbers together, and all the variables

0.12y+0.02(y-6)-(0.10y-0.051)=0

We multiply parentheses

0.12y+0.02y-(0.10y-0.051)-0.12=0

We get rid of parentheses

0.12y+0.02y-0.10y+0.051-0.12=0

We add all the numbers together, and all the variables

0.04y-0.069=0

We move all terms containing y to the left, all other terms to the right

0.04y=0.069

y=0.069/0.04

y=1+0.029/0.04

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