6(b-3)=4(b+22)

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Solution for 6(b-3)=4(b+22) equation: 



6(b-3)=4(b+22)

We move all terms to the left:

6(b-3)-(4(b+22))=0

We multiply parentheses

6b-(4(b+22))-18=0



We calculate terms in parentheses: -(4(b+22)), so:

4(b+22)

We multiply parentheses

4b+88

Back to the equation:

-(4b+88)



We get rid of parentheses

6b-4b-88-18=0

We add all the numbers together, and all the variables

2b-106=0

We move all terms containing b to the left, all other terms to the right

2b=106

b=106/2

b=53

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