0.02(2t-1)=0.12(t-2)+0.18

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Solution for 0.02(2t-1)=0.12(t-2)+0.18 equation: 



0.02(2t-1)=0.12(t-2)+0.18

We move all terms to the left:

0.02(2t-1)-(0.12(t-2)+0.18)=0

We multiply parentheses

0.04t-(0.12(t-2)+0.18)-0.02=0



We calculate terms in parentheses: -(0.12(t-2)+0.18), so:

0.12(t-2)+0.18

We multiply parentheses

0.12t-0.24+0.18

We add all the numbers together, and all the variables

0.12t-0.06

Back to the equation:

-(0.12t-0.06)



We get rid of parentheses

0.04t-0.12t+0.06-0.02=0

We add all the numbers together, and all the variables

-0.08t+0.04=0

We move all terms containing t to the left, all other terms to the right

-0.08t=-0.04

t=-0.04/-0.08

t=0.04/0.08

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