0.02(2t-1)=0.04(t-5)+0.18

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Solution for 0.02(2t-1)=0.04(t-5)+0.18 equation: 



0.02(2t-1)=0.04(t-5)+0.18

We move all terms to the left:

0.02(2t-1)-(0.04(t-5)+0.18)=0

We multiply parentheses

0.04t-(0.04(t-5)+0.18)-0.02=0



We calculate terms in parentheses: -(0.04(t-5)+0.18), so:

0.04(t-5)+0.18

We multiply parentheses

0.04t-0.2+0.18

We add all the numbers together, and all the variables

0.04t-0.02

Back to the equation:

-(0.04t-0.02)



We get rid of parentheses

0.04t-0.04t+0.02-0.02=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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