1/3x+3=2x

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Solution for 1/3x+3=2x equation:



1/3x+3=2x
We move all terms to the left:
1/3x+3-(2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
-2x+1/3x+3=0
We multiply all the terms by the denominator
-2x*3x+3*3x+1=0
Wy multiply elements
-6x^2+9x+1=0
a = -6; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·(-6)·1
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*-6}=\frac{-9-\sqrt{105}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*-6}=\frac{-9+\sqrt{105}}{-12} $

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