0.007(2-k)+0.02(k-6)=1

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Solution for 0.007(2-k)+0.02(k-6)=1 equation: 



0.007(2-k)+0.02(k-6)=1

We move all terms to the left:

0.007(2-k)+0.02(k-6)-(1)=0

We add all the numbers together, and all the variables

0.007(-1k+2)+0.02(k-6)-1=0

We multiply parentheses

-0.007k+0.02k+0.014-0.12-1=0

We add all the numbers together, and all the variables

0.013k-1.106=0

We move all terms containing k to the left, all other terms to the right

0.013k=1.106

k=1.106/0.013

k=85+0.0010000000000001/0.013

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