(3y+13)=(4y-1)

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Solution for (3y+13)=(4y-1) equation: 



(3y+13)=(4y-1)

We move all terms to the left:

(3y+13)-((4y-1))=0

We get rid of parentheses

3y-((4y-1))+13=0



We calculate terms in parentheses: -((4y-1)), so:

(4y-1)

We get rid of parentheses

4y-1

Back to the equation:

-(4y-1)



We get rid of parentheses

3y-4y+1+13=0

We add all the numbers together, and all the variables

-1y+14=0

We move all terms containing y to the left, all other terms to the right

-y=-14

y=-14/-1

y=+14

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