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0-5x(46+89x)=26x
We move all terms to the left:
0-5x(46+89x)-(26x)=0
We add all the numbers together, and all the variables
-5x(89x+46)-26x+0=0
We add all the numbers together, and all the variables
-26x-5x(89x+46)=0
We multiply parentheses
-445x^2-26x-230x=0
We add all the numbers together, and all the variables
-445x^2-256x=0
a = -445; b = -256; c = 0;
Δ = b2-4ac
Δ = -2562-4·(-445)·0
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{65536}=256$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-256)-256}{2*-445}=\frac{0}{-890} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-256)+256}{2*-445}=\frac{512}{-890} =-256/445 $
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