0-(3x-1)/(2)=(6x+3)/(11)

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Solution for 0-(3x-1)/(2)=(6x+3)/(11) equation: 



0-(3x-1)/(2)=(6x+3)/(11)

We move all terms to the left:

0-(3x-1)/(2)-((6x+3)/(11))=0

We add all the numbers together, and all the variables

-(3x-1)/2-((6x+3)/11)=0

We calculate fractions


(-3x)/()+(-((6x+3)*2)/()=0



We calculate terms in parentheses: +(-((6x+3)*2)/(), so:

-((6x+3)*2)/(

We multiply all the terms by the denominator


-((6x+3)*2)



We calculate terms in parentheses: -((6x+3)*2), so:

(6x+3)*2

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

-12x-6

Back to the equation:

+(-12x-6)



We get rid of parentheses

(-3x)/()-12x-6=0

We multiply all the terms by the denominator


(-3x)-12x*()-6*()=0

We add all the numbers together, and all the variables

(-3x)-12x*()=0

We get rid of parentheses

-3x-12x*()=0

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