0,2(7-2y)=2,3-0,3(y-6)

Solution for 0,2(7-2y)=2,3-0,3(y-6) equation:

0.2(7-2y)=2.3-0.3(y-6)

We move all terms to the left:

0.2(7-2y)-(2.3-0.3(y-6))=0

We add all the numbers together, and all the variables

0.2(-2y+7)-(2.3-0.3(y-6))=0

We multiply parentheses

-0.4y-(2.3-0.3(y-6))+1.4=0


We calculate terms in parentheses: -(2.3-0.3(y-6)), so:

2.3-0.3(y-6)

determiningTheFunctionDomain
-0.3(y-6)+2.3

We multiply parentheses

-0.3y+1.8+2.3

We add all the numbers together, and all the variables

-0.3y+4.1

Back to the equation:

-(-0.3y+4.1)


We get rid of parentheses

-0.4y+0.3y-4.1+1.4=0

We add all the numbers together, and all the variables

-0.1y-2.7=0

We move all terms containing y to the left, all other terms to the right

-0.1y=2.7

y=2.7/-0.1

y=-27