2x-3(x+2)=5-2(3-2x)

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Solution for 2x-3(x+2)=5-2(3-2x) equation: 



2x-3(x+2)=5-2(3-2x)

We move all terms to the left:

2x-3(x+2)-(5-2(3-2x))=0

We add all the numbers together, and all the variables

2x-3(x+2)-(5-2(-2x+3))=0

We multiply parentheses

2x-3x-(5-2(-2x+3))-6=0



We calculate terms in parentheses: -(5-2(-2x+3)), so:

5-2(-2x+3)

determiningTheFunctionDomain
-2(-2x+3)+5

We multiply parentheses

4x-6+5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

-1x-(4x-1)-6=0

We get rid of parentheses

-1x-4x+1-6=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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