0,2(0,1-x)-0,3(0,2-x)=0,4(0,4-x)

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Solution for 0,2(0,1-x)-0,3(0,2-x)=0,4(0,4-x) equation: 



0.2(0.1-x)-0.3(0.2-x)=0.4(0.4-x)

We move all terms to the left:

0.2(0.1-x)-0.3(0.2-x)-(0.4(0.4-x))=0

We add all the numbers together, and all the variables

0.2(-1x+0.1)-0.3(-1x+0.2)-(0.4(-1x+0.4))=0

We multiply parentheses

-0.2x+0.3x-(0.4(-1x+0.4))+0.02-0.06=0



We calculate terms in parentheses: -(0.4(-1x+0.4)), so:

0.4(-1x+0.4)

We multiply parentheses

-0.4x+0.16

Back to the equation:

-(-0.4x+0.16)



We add all the numbers together, and all the variables

0.1x-(-0.4x+0.16)-0.04=0

We get rid of parentheses

0.1x+0.4x-0.16-0.04=0

We add all the numbers together, and all the variables

0.5x-0.2=0

We move all terms containing x to the left, all other terms to the right

0.5x=0.2

x=0.2/0.5

x=0.2/0.5

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