5=1/3(x+7)

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Solution for 5=1/3(x+7) equation: 



5=1/3(x+7)

We move all terms to the left:

5-(1/3(x+7))=0



Domain of the equation: 3(x+7))!=0

x∈R



We multiply all the terms by the denominator


-(1+5*3(x+7))=0



We calculate terms in parentheses: -(1+5*3(x+7)), so:

1+5*3(x+7)

determiningTheFunctionDomain
5*3(x+7)+1

Wy multiply elements

15x(x+1

Back to the equation:

-(15x(x+1)





We calculate terms in parentheses: -(15x(x+1), so:

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15x(x+1





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15x(x+1





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15x(x+1





We calculate terms in parentheses: -(15x(x+1), so:

15x(x+1





We calculate terms in parentheses: -(15x(x+1), so:

15x(x+1





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15x(x+1





We calculate terms in parentheses: -(15x(x+1), so:

15x(x+1





We calculate terms in parentheses: -(15x(x+1), so:

15x(x+1





We calculate terms in parentheses: -(15x(x+1), so:

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We calculate terms in parentheses: -(15x(x+1), so:

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We calculate terms in parentheses: -(15x(x+1), so:

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We calculate terms in parentheses: -(15x(x+1), so:

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We calculate terms in parentheses: -(15x(x+1), so:

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We calculate terms in parentheses: -(15x(x+1), so:

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