0(t)=80t-16t2

Solution for 0(t)=80t-16t2 equation:

0(t)=80t-16t^2

We move all terms to the left:

0(t)-(80t-16t^2)=0

We add all the numbers together, and all the variables

-(80t-16t^2)+t=0

We get rid of parentheses

16t^2-80t+t=0

We add all the numbers together, and all the variables

16t^2-79t=0

a = 16; b = -79; c = 0;
Δ = b2-4ac
Δ = -792-4·16·0
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-79}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+79}{2*16}=\frac{158}{32}
=4+15/16
$