/x2-5=-3

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Solution for /x2-5=-3 equation: 



/x2-5=-3

We move all terms to the left:

/x2-5-(-3)=0



Domain of the equation: x2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

/x2-2=0

We multiply all the terms by the denominator


-2*x2+=0

We add all the numbers together, and all the variables

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$

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