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/x-6=5x+10
We move all terms to the left:
/x-6-(5x+10)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
/x-5x-10-6=0
We multiply all the terms by the denominator
-5x*x-10*x-6*x+=0
We add all the numbers together, and all the variables
-16x-5x*x=0
Wy multiply elements
-5x^2-16x=0
a = -5; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-5)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-5}=\frac{0}{-10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-5}=\frac{32}{-10} =-3+1/5 $
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