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/8x-3(2x-4)=3(x-6)
We move all terms to the left:
/8x-3(2x-4)-(3(x-6))=0
Domain of the equation: 8x!=0We multiply parentheses
x!=0/8
x!=0
x∈R
/8x-6x-(3(x-6))+12=0
We multiply all the terms by the denominator
-6x*8x-((3(x-6)))*8x+12*8x+=0
We add all the numbers together, and all the variables
-6x*8x-((3(x-6)))*8x+12*8x=0
Wy multiply elements
-48x^2-((3(x-6)))*8x+96x=0
We add all the numbers together, and all the variables
-48x^2+96x-((3(x-6)))*8x=0
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